A 210 cm 210 cm square loop of wire with resistance 120102

A 2.10 cm × 2.10 cm square loop of wire with resistance 1.20×10?2 ? has one edge parallel to a long straight wire. The near edge of the loop is 1.20 cm from the wire. The current in the wire is increasing at the rate of 120 A/s . What is the current in the loop in ?A?

« previous 2 of 6 | next >» Prayer 2 Part A A 2.10 cm × 2.10 cm square loop of wire with resistance 1.20×10-2 has one edge parallel to a long straight wire. The near edge of the loop is 1.20 cm from the wire. The current in the wire is increasing at the rate of 120 A/s What is the current in the loop? HA Submit My Answers Give Up Provide Feedback Continue

Solution

The near edge of the loop c = 0.012 m

length of side of square loop a = b = 0.021 m

resistance R = 1.2*10^-2 and current rate dI/dt = 120 A/s

the loop current is calculated as follows:

I _loop= (₀b/2R)(dI/dt)[ln(c + a / c)]

= [(4*10^-7)(0.021) /(2)()(1.2*10^-2)](120)[ln(0.021 + 0.012 / 0.012)]

=87.28*10^-6 A

  = 87.28 A