A 498m long spaceship passes by an observer at the speed of
A 498-m long spaceship passes by an observer at the speed of 2.50×108 m/s. What length does the observer measure for the spaceship?
Solution
L = Lp * sqrt [1 - v2/c2]
L = 498 * sqrt [1 - (2.5 * 108)2/(3 * 108)2]
L = 275.28 m

