A particle has an initial velocity of 3 fts to the left at s

A particle has an initial velocity of 3 ft/s to the left at s_0 = 0 ft. Determine its position when t = 3 s if the acceleration is 2 ft/s^2 to the right. A) 0.0 ft B) 6.0 ft leftarrow C) 18.0 ft rightarrow D) 9.0 ft rightarrow

Solution

Using equation of motion

S = ut + 1/2 at²......................(A)

Where, S = displacement

u = initial velocity

t = time

a = acceleartion

In this case

u = 3 ft/s

t = 3 s

a = -2 ft/s² ( As direction of accerleration is opposite to direction of motion)

Using the values in the equation (A)

S = 0

So the particle will come to initial position

Ans (A) 0.0 ft