10 pts 7 580000 when she dies Let X Bettys the net profit Ba
Solution
7)
we know that when she die she will pay $80,000 and if she lives she will pay $900
the probability of she lives is 0.995 and the probability of she dies is 1-0.995 = 0.005
Expect value is: 900*0.995 + 80,000*0.005 = 1,295.5
x^2*P(x)= 900^2*0.995 + 80,000^2 * 0.005 = 32,805,950
standard deviation= sqrt(32,805,950 - 1,295.5)
standard deviation: 5,727.53
The expected value represents the average value which is expected, by repeating the experiment independently a lot of times
So for this case presents the average value which is expected to pay in the posibilities of dies and lives
8)
Well As we know this is a binomial distribution and for the binomial model use the bernoulli trials
Independent means that the outcome of one trial does not affect the outcome of the other,
and we can see that are approximately independents because
each passenger can either a arrive for the flight or a non-arrive for the flight; arrive for the flight being a success here
if a passenger can arrive for the flight not affect that other passenger can arrive or non arrive for the flight
N= sample that is 20
p= success that is 0.85
q= fail that is 1-0.85 = 0.15
| X | P(x) | |
| lives | 900 | 0.995 | 
| Dies | 80,000 | 0.005 | 
![[10 pts.] 7 580,000 when she dies. Let X Betty\'s the net profit. Based on mortality 0.995 chance that Betty will live until the next year Betty Binomial pays   [10 pts.] 7 580,000 when she dies. Let X Betty\'s the net profit. Based on mortality 0.995 chance that Betty will live until the next year Betty Binomial pays](/WebImages/28/10-pts-7-580000-when-she-dies-let-x-bettys-the-net-profit-ba-1075353-1761563915-0.webp)
