Use a FOR loop starting at RL 0 having an ohmic step size of

Use a FOR loop starting at R_L =0 having an ohmic step size of 0.001 ohms to find the value of R_L which makes power P maximum. You will need to include an appropriate IF statement in your code to determine when the maximum value of P is reached and stop the FOR loop using the BREAK command. Lastly, use FPRINTF command to print out the solution found for the value of R_L and the corresponding value of load power P.

Solution

Ans)

Matlab code here

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RL=0:0.001:40;
P(1)=RL(1)*(10/(RL(1)+20))^2;
for i=2:length(RL)
  
P(i)=RL(i)*(10/(RL(i)+20))^2;

if P(i)<P(i-1)

fprintf(\'Maximum Power=%2.2f W, RL=%2.2f ohms\ \',P(i-1),RL(i-1));
break

end

end
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Result here in command window

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>> maxPower
Maximum Power=1.25 W, RL=20.00 ohms
>>

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One suggestion to you while asking the question you should also provide information of Power equation ,as I get the first question I was able to answer this ,if some one else got this they don\'t have sufficient information