Find the slope intercept form of the equation of a line that

Find the slope -intercept form of the equation of a line that passes through the given points. (6,-9),(-2,3)

Solution

First thing you have to do is get the slope

(y2-y1)/(x2-x1) = slope

lets make (6,-9) point 1, and (-2,3) point 2 you dont really need to do this part but it helps
so x1 = 6 y1 = -9 x2 = -2 y2 =3

(3 - -9)/(-2 - 6) = 12/-8 or -3/2

now the Point-Slope Equation of a Line is y - y1 = m(x - x1)

so lets plug in
Y - -9 = (-3/2)(X - 6) or

Y +9 = (-3/2)(X-6)