Given X N10 18 and n 64 xbar N10 SolutionIf XNu sigma2 The

Given X ~N(10, 18) and n = 64 x-bar ~ N(10, _________)

Solution

If

X~N(u, sigma^2)

Then

xbar~N(u, sigma^2/n)

Thus,

xbar~N(10, 18/64)

or

xbar~N(10, 0.28125) [ANSWER]

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Note: Here, I assumed that the second number is the variance. If it is actually the standard deviation, then please use

xbar~N(u, sigma/sqrt(n))

Thus,

xbar~(10, 18/sqrt(64))

xbar~(10, 2.25) [alternate answer]