A kite on a 100ft string has an angle of elevation of 18 deg

A kite on a 100-ft string has an angle of elevation of 18 degree. The hand holding the string is 4 ft from the ground. How high above the ground is the kite? a. 95 ft b. 35 ft c. 31 ft d. 22 ft

Solution

Sin(theta) = x/h

h = 100 ft

theta = 18 degrees

h = 100 sin (18) = 30.9

The hand holding the string is 4 ft from the ground

so the height of the kite above the ground is = 30.9 + 4 = 34.9

= 35 ft