A cylindrical hole is bored through a steel block and a cyli

A cylindrical hole is bored through a steel block, and a cylindrical piston is machined to fit into the hole. The diameter of the hole is 20.00 ± 0.01 cm, and the diameter of the piston is 19.90 ± 0.02 cm. The clearance is one-half the difference between the diameters.

1.)Using WCA, determine if the piston assembly will meet the specified clearance of 0.04 cm.

2.)Using RSS, determine the probability that the clearance will be less than 0.04 cm.

Remember to convert tolerances to standard deviation by assuming a safety factor of 3.

Solution

1)

20 - 19.90 = 0.1

0.01 + 0.02 = 0.03

the piston will not specified clearence of 0.04

2)

0.03 / 0.04 = 0.75