A box contains 4 white balls and 3 red balls 2 balls are tak

A box contains 4 white balls and 3 red balls. 2 balls are taken out at random without
replacement. Let A be the event of getting one white and one red balls. Find P(A) using the product
rule. Hint: consider order.

Solution

event of getting one white and one red balls = 1/4 *1/3

total outcomes = (onewhite +one red ) +2 white+2 red +(one red+one white)

=(1/4 *1/3)+ 2/4 + 2/3 + (1/3 *1/4)

P(A) =1/4 *1/3 /(1/4 *1/3)+ 2/4 + 2/3 + (1/3 *1/4)

P(A) = 1/12 / (1/12+2/4+2/3+1/12)

=0.0625