Find an equation of the tangent line to the curve at the giv

Find an equation of the tangent line to the curve at the given point y=4x-3x^2, (2,-4).

y=4x-3x^2, (2,-4).

slope = y\' = dy/dx = 4-6x

slope at x= 2

4-6*2 = 5-12 = -8

eqaution of tangnet

y+4 = -8(x-2)

y = -8x +16 -4 = -8x+12

$Find an equation of the tangent line to the curve at the given point y=4x-3x^2, (2,-4).Solutiony=4x-3x^2, (2,-4). slope = y\' = dy/dx = 4-6x slope at x= 2 4-6*2$

Find an equation of the tangent line to the curve at the giv

Solution

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