Suppose that the IQ scores of a certain population have an a
Suppose that the IQ scores of a certain population have an approximate normal distribution with mean 100.8 and standard deviation 14.3. What fraction of the population has an IQ score less than 120.5?
Solution
Let X be the IQ scores
mu = 100.8 and sigma =14.3
For finding the fraction we have to find the prob for X< 120.5
z score = 120.5-100.8/14.3 = -1.38
Prob = 0.4162
Hence 41.62% of the population is answer
