5 1516171 ACATTTGCTTATGGTGCATCTGACTCCTGAGG 491621 AGTATCACTA

5-
1.......................51..................61......................71
ACATTTGCTT:::ATGGTGCATCTGACTCCTGAGG
......................491..........621
AG:::TATCACTAAGCT:::CATTGC-3

N-MET -VAL- HIS- LEU- THR- PRO- GLU- GLU :::TYR- HIS -C

Understand that the (:::) represents intervening amino acids. The entire polypeptide is 147 amino acids long. How could that be calculated from the information given above?

Solution

Each and every amino acid is coded by a triplet codon (a combination of 3 nucleotides). so for the 147 amino acids,there should be 147*3 = 441 nucleotides(in the above sequation) for the translation.

5- 1.......................51..................61......................71 ACATTTGCTT:::ATGGTGCATCTGACTCCTGAGG ......................491..........621 AG:::TATCAC

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