Statistics indicate that the rainfall in Ithaca New York has
Solution
Mean ( u ) =35.4
Standard Deviation ( sd )=4.2
Normal Distribution = Z= X- u / sd ~ N(0,1)
a)
P(X > 40) = (40-35.4)/4.2
= 4.6/4.2 = 1.0952
= P ( Z >1.095) From Standard Normal Table
= 0.1367
13.67 ~ 14% of years does ithaca is the mean rainfall
more than 40
b)
P ( Z < x ) = 0.2
Value of z to the cumulative probability of 0.2 from normal table is -0.842
P( x-u/s.d < x - 35.4/4.2 ) = 0.2
That is, ( x - 35.4/4.2 ) = -0.84
--> x = -0.84 * 4.2 + 35.4 = 31.8636
It is about 31.86
d)
Mean ( u ) =35.4
Standard Deviation ( sd )=4.2/ Sqrt ( 4 ) = 2.1
Number ( n ) = 4
Normal Distribution = Z= X- u / (sd/Sqrt(n) ~ N(0,1)
P(X > 30) = (30-35.4)/4.2/ Sqrt ( 4 )
= -5.4/2.1= -2.5714
= P ( Z >-2.5714) From Standard Normal Table
= 0.9949
P(X < = 30) = (1 - P(X > 30)
= 1 - 0.9949 = 0.0051
