A soft drink machine outputs a mean of 27 ounces per cup The

A soft drink machine outputs a mean of 27 ounces per cup. The machine\'s output is normally distributed with a standard deviation of 4 ounces. What is the probability of putting less than 33 ounces in a cup?

Solution

The probability is

P(X<33) = P((X-mean)/s <(33-27)/4)

=P(Z<1.5) = 0.9332 (from standard normal table)