Homework SourseThe airline industry defines noshows as passengers who have
The airline industry defines? no-shows as passengers who have purchased a ticket but fail to arrive at the gate on time for departure. An airline operates many flights from City A to City B and experienced the accompanying? no-show probability distribution last year. The accompanying data shows the number of? no-shows that occurred on a random sample of 120 flights between these two cities this year. The airline would like to know if the probability distribution of? no-shows has changed between last year and this year on flights between these two cities using
alpha?equals=0.05.
What is the critical value for this hypothesis? test? Round to three decimal places.
?No-Show Distribution from Previous Year
?No-shows
0
1
2
3
4
5
6
Probability
?6%
?12%
?22%
?28%
?17%
?11%
?4%
?No-Show Sample from This Year
?No-shows
0
1
2
3
4
5
6
Frequency
3
13
37
31
22
4
10
| ?No-shows | 0 | 1 | 2 | 3 | 4 | 5 | 6 |
| Probability | ?6% | ?12% | ?22% | ?28% | ?17% | ?11% | ?4% |
Solution
Ans:
Test statistic:
Chi square score=19.214
df=7-1=6
Critical chi square score=CHIINV(0.05,6)=12.592
As,test statistic is greater than 12.592,we reject the null hypothesis and we can conclude that the probability distribution of no-shows has changed.
| No shows | Observed(fo) | pi | Expected(fe) | (fo-fe)^2/fe |
| 0 | 3 | 0.06 | 7.2 | 2.450 |
| 1 | 13 | 0.12 | 14.4 | 0.136 |
| 2 | 37 | 0.22 | 26.4 | 4.256 |
| 3 | 31 | 0.28 | 33.6 | 0.201 |
| 4 | 22 | 0.17 | 20.4 | 0.125 |
| 5 | 4 | 0.11 | 13.2 | 6.412 |
| 6 | 10 | 0.04 | 4.8 | 5.633 |
| Total= | 120 | 1 | 120 | 19.214 |
