Using Verilog design a mod60 BCD counter that performs a cou
Solution
verilog code for Mod 60:
module mod60 ( clk ,clear ,BCD1,BCD0 );
 output reg [3:0] BCD1 ;
 output reg [3:0] BCD0 ;
 reg [7:0] dout ;
 input clk ;
 wire clk ;
 input clear ;
 wire clear ;
initial dout = 0 ;
always @ (posedge (clk)) begin
 if (clear)
 dout <= 0;
 else if (dout<=59) begin
 dout <= dout + 1;
 end
else if (dout==60)
begin
 dout <= 0;
 end
 BCD1=dout[7:4];
 BCD0=dout[3:0];
 end
 endmodule
for mod-24:
verilog code for Mod 60:
module mod60 ( clk ,clear ,BCD1,BCD0 );
 output reg [3:0] BCD1 ;
 output reg [3:0] BCD0 ;
 reg [7:0] dout ;
 input clk ;
 wire clk ;
 input clear ;
 wire clear ;
initial dout = 0 ;
always @ (posedge (clk)) begin
 if (clear)
 dout <= 0;
 else if (dout<24) begin
 dout <= dout + 1;
 end
else if (dout==24) begin
 dout <= 0;
 end
 BCD1=dout[7:4];
 BCD0=dout[3:0];
 end
 endmodule


