61 ASolutionA a2sin1 sin 12 360ok 30o360ok 150o b30o150o B5

6.1

A)

Solution

A)

a)2sin=1

sin= 1/2

=360^ok +30^o,360^ok +150^o

b)=30^o,150^o

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B)5cost-3 =3cost

a)5cost-3cost =3

2cost=3

cost=3_/2

t=2k -_/6,t=2k +_/6

b)t= _/6,11_/6

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C)

a)2sint +5 =-3sint

2sint +3sint =-5

5sint =-5

sint =-1

t =2k +3_/2

b) t =3_/2