A man throws a ball upwards giving it an initial speed of v0

A man throws a ball upwards giving it an initial speed of v_0 = 50 meters/second. The ball has a mass of 10 kg and is released at a height of X_0 = 4 meters above the ground. The height h of greatest ascent above the ground is:

the greatest height achieved by the ball is calculated as follows:

H_max = x₀ + v₀²/2g = 4 + (50^2/2*9.8) = 131.55 m = 132 m (nearly)