The number of heart beats per minute of a mouse varies from
The number of heart beats per minute of a mouse varies from mouse to mouse. Suppose that the number of beats per minute of 15 mice is measure. The sample mean for these 15 mice is 39 beats. The STANDARD ERROR for the sample mean is 0.8. Using this information (a) find the standard deviation for a the heart beat of a mouse and (b) how large a sample size do I need for the margin of error for a 95% confidence interval to be to 0.5 (use the normal distribution)?
A) The standard deviation is 3.1 (this is the variability in heart beats between mice). Therefore solving the equation the minimum sample size is 148.
B) The standard deviation is 3.1 (this is the variability in heart beats between mice). Therefore solving the equation the minimum sample size is 10.
C) The standard deviation is 0.8 (this is the variability in heart beats between mice). Therefore solving the equation the minimum sample size is 10.
D) The standard deviation is 0.2 (this is the variability in heart beats between mice). Therefore solving the equation the minimum sample size is 1.
E) The standard deviation is 12 (this is the variability in heart beats between mice). Therefore solving the equation the minimum sample size is 2213.
Please show the work used to solve for the answers and not just the actual answer alone!
Solution
