alculek n 12 3511 292 3 SolutionT pi2 x r cos t y r sin t

alculek n 12 #3511 292 3

Solution

T = pi/2

x = r cos t

y = r sin t

for unit circle r = 1

and t we have pi/2

hence, points are

x = cos ( pi/2 ) = 0

y = sin ( pi/2 ) = 1

( x, y ) = ( 0 , 1)

2) t = pi/6

x = r cos t

y = r sin t

x = cos ( pi/6 ) = sqrt 3/2

y = sin pi/6 = 1/2

( x, y) = ( sqrt 3/2 , 1/2 )

 alculek n 12 #3511 292 3 SolutionT = pi/2 x = r cos t y = r sin t for unit circle r = 1 and t we have pi/2 hence, points are x = cos ( pi/2 ) = 0 y = sin ( pi/

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