alculek n 12 3511 292 3 SolutionT pi2 x r cos t y r sin t
alculek n 12 #3511 292 3
Solution
T = pi/2
x = r cos t
y = r sin t
for unit circle r = 1
and t we have pi/2
hence, points are
x = cos ( pi/2 ) = 0
y = sin ( pi/2 ) = 1
( x, y ) = ( 0 , 1)
2) t = pi/6
x = r cos t
y = r sin t
x = cos ( pi/6 ) = sqrt 3/2
y = sin pi/6 = 1/2
( x, y) = ( sqrt 3/2 , 1/2 )
