It is said that happy and healthy workers are more efficient
Solution
a)
Note that
p^ = point estimate of the population proportion = x / n = 0.333333333
Also, we get the standard error of p, sp:
sp = sqrt[p^ (1 - p^) / n] = 0.030429031
Now, for the critical z,
alpha/2 = 0.015
Thus, z(alpha/2) = 2.170090378
Thus,
Margin of error = z(alpha/2)*sp = 0.066033747
lower bound = p^ - z(alpha/2) * sp = 0.267299586
upper bound = p^ + z(alpha/2) * sp = 0.399367081
Thus, the confidence interval is
( 0.267299586 , 0.399367081 ) [ANSWER]
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b)
As we can see in the confidence interval, 0.30 is inside it. So, there is no significant evidence that the proportion of companies that provide such facilities on site is distinct from the overall proportion. [CONCLUSION]
