please post answers in text format thank you discuss the fol

please post answers in text format thank you

discuss the following voltage values across a inductor when DC voltage applied to an RL circuit:
Assume the value of R=1K and L=10mH and initially inductor is not charged.
What is time constant?
at t=0, what is voltage across inductor? What is the circuit current value?
at t=time constant , what is voltage across inductor? What is the circuit current value?
at t=2*time constant , what is voltage across inductor? What is the circuit current value?
at t=3*time constant , what is voltage across inductor? What is the circuit current value?
at t=4* time constant , what is voltage across inductor? What is the circuit current value?
at t=5* time constant , what is voltage across inductor? What is the circuit current value?
Observation:
~ Do you think inductor acts as an open circuit in the beginning of charging cycle (t=0) ? If yes, why?
~ Do you think inductor acts a short circuit in the end of charging cycle (t=5RC) ? If yes, why?
This will help us to work on our homework problems.
Write down the answers only. If possible post the formulas you used to calculate those numbers. Each one can solve at least two questions. That way we all can contribute to solve this segment and have a great understanding of transient behavior of an inductor.

Solution

when the inductor is in initial or final condition the timeconstant is same it will be always

time constant=L/R=(10*10^-3)/(1*10^3)=1*10^-5

i=io(e^-t/T)

v=Vo(1-e^-t/T)

at t=0

i=v*10^-3 amp

v=0 volts

at t=time constant

i=3.678*10^-4 amps

v=0.632*v volts

at t=2*time constant

i=1.32*10^-4*v amps

v=0.8646*v volts

at t=3*timeconstant

i=4.97*10^-5*v amps

v=0.9502*v volts

at t=4*timeconstant

i=1.83*10^-5 amps

v=0.9816*v volts

at t=5*timeconstant

i=0.737*10^-6*v amps

v=0.9932*v volts

In the beginning inductor acts like a short circuit and in the end its acts like a open circuit.