Individual MM plain candies have weights that are normally d
Individual M&M plain candies have weights that are normally distributed with
a mean weight of 0.8565 g and a standard deviation of 0.0518 g.
If you randomly select 1 M&M plain candy, what is the probability
that the candy will weigh less than 0.8535 g?
Round your answer to three decimal places.
Solution
So the probability is
P(X<0.8535) = P((X-mean)/s <(0.8535-0.8565)/0.0518)
=P(Z<-0.06) =0.476 (from standard normal table)
