The Excel output in Figure 2 below was generated using a sig
The Excel output in Figure 2 below was generated using a significance level of 0.10. Which assumption was made to generate this output?
Figure 2: Comparing mean batting averages between the American and National League
Select one:
a. The population variances are equal
b. The population variances are not equal
c. The sample variances are equal
d. The sample variances are not equal
Question 6
Not yet answered
Marked out of 4
Flag question
Question text
Using the Excel output in Figure 2, with a two-tail test what would you conclude using a significance level of 0.10?
Select one:
a. The batting averages for the two leagues are the same
b. The batting average for the American League is greater than the National League\'s average
c. The batting averages for the two leagues are different
d. The batting averages vary in the same way
Question 7
Not yet answered
Marked out of 4
Flag question
Question text
Using the same Excel output in Figure 2, even if the two unknown population means are indeed equal, why would we not be surprised to find that our twosample means are different?
Select one:
a. Because population data is not complete
b. Because of sampling error
c. Because sample means are always less than population means
d. Because sample means are always greater than population means
t-Test: Two-Sample Assuming Unequal Variances AL NL Mean Variance Observations Hypo df t Stat P(TSolution
b. The population variances are not equal
The assumption about variance is taken for population in consideration not the sample.
Problem 6
When we are checking whether the two leagues have different or same batting averages we will use the two tailed probability for refence. Here it is given to be 0.55913 which is greater than significance level(0.10). Thus the two leagues must have same batting averages.
a. The batting averages for the two leagues are the same
Problem 7.
b. Because of sampling error
While picking up samples, we may select two completely different set of samples for the two groups , thus leading to difference in the mean of two groups, even when their population has same mean.

