Evaluate the limit using LHospitals rule Suppose that Soluti

Evaluate the limit using L\'Hospital\'s rule Suppose that

Solution

As it is 0/0 form

Apply L Hospital Rude

FDifferentiate Numenator and Denominator w.r.t x , we get

lim(x--->0) (11^xln11 - 2^xln2)/(1)

= (11⁰ln11 - 2⁰ln2)

= ln(11/2)

= 1.7047

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f\'(x) = 1/(2(4+(5x))*(d/dx)((4+(5x))

=  1/(2(4+(5x))*(1 + 5(1/(2x))