Write out what prints to matlab at each step performing the

Write out what prints to matlab at each step performing the false position method in Matlab with the code located below. Assume that func=sin(x)-x^2 and xl=0.5 and xu=1. iter=0 xx=xl while(0) xo=xx fl=func(xl, varargin{:}) fu=func(xu, varargin{:}) xx=xu-fu*(xl-xu)/(fl-fu) iter=iter+1 if xx~=0,ea=abs((xx-xo))/xx*100;end test=fl*func(xx, varargin{:}) if test0 xl=xx else ea=0 end

Solution

Output of MATLAB at each step is as below:

iter =0

xx = 0.5

xo = 0.5

fl = 0.2294

fu = -0.1585

xx = 0.7957

iter = 1

test = -0.4692

xu = 0.7957