Please show detailed work For the mechanisms shown point C m
Solution
Given:
Angular Velocity at A= 20Rad/Sec
Acceleration at A = 140 Rad/sec2
AB=BC=BD=100mm =0.1m
Formula to be used: Velocity = Ang. Vel X Radius
Acceleration = Vel 2 /Radius
Line Diagram of the Problem
Angular Velocity of B w.r.t A = Angular Velocity of Link A
(b)a = 20Rad/Sec.
(Vb)a = 20 X 0.1
= 2m/sec
(Vb)a = (Vc)b
(Vc)b = 2m/sec. Answer
Acceleration at Pt. C W.R.T B
a(cb) = (2)2 X 0.1
a(cb) = 40m/sec2 Answer
Angular Velocity (3) of Link 3 = Angular Velocity (2) of Link 2
3 = 20 Rad/Sec
Acceleration of Link 3 WRT B (3B) = (3)2 X R
= (20)2 X 0.2
Acceleration of Link 3 WRT B (3B) = 80m/sec2
Answers:
