For the Beam shown the Max BM at point D will be 12 kips ft

For the Beam shown, the Max BM at point D will be 12 kips, ft 6 Kips. ft 12 kips. ft 48 Kips. ft

Solution

ans:

   option( A )

  from the given beam

BM at any section:

M=wLx/2-wx.x/2

=w/2(Lx-x² )

the maximum BM at point \"D\" is

M_max=wL²/8 [M at dM/dx=V=0]

where w=1.5 kips/ft

L=8ft

M_{max=(1.5*8²)/8}

   _=1.5*8

M_{max=12 kips.ft}

maximum BM at point \"D\" is 12 kips.ft