A hotair balloon is rising straight up with a speed of 2 ms

A hot-air balloon is rising straight up with a speed of 2 m/s. A ballast bag is released from rest relative to the balloon at 8.8 m above the ground. How much time elapses before the ballast bag hits the ground?

Solution

1/2 a_y t² + v_0y t - y = 0

1/2 (-9.8) t² + 2 t + 8.8 = 0

-4.9 t² + 2 t + 8.8 = 0

t = -2.0 + sqrt [4 - (4 * -4.9 * 8.8)] / (2 * -4.9)

= 1.6 s