| 3. | A continuous population has a mean of 210.51 and a standard deviation of 10.31. Suppose we know that the population is normally distributed. Compute the smallest interval centered on the mean that will contain 95% of the observations. |
| | a.(200.20, 220.82) | | b.(164.40, 256.62) | | c.(189.89, 231.13) | | d.(179.58, 241.44) | |
| 3. | A continuous population has a mean of 210.51 and a standard deviation of 10.31. Suppose we know that the population is normally distributed. Compute the smallest interval centered on the mean that will contain 95% of the observations. |
| | a.(200.20, 220.82) | | b.(164.40, 256.62) | | c.(189.89, 231.13) | | d.(179.58, 241.44) | |
Let X~ N(µ,2)
Then 95 % confidence intervalis given by [µ- .025,µ+ .025] = [µ-1.96,µ+1.96] = [189.89,231.13]
Hence option c is correct.
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