a Describe an atom which is an iisotope ii isotone and a ii
a. Describe an atom which is an i.isotope, ii. isotone, and a ii. isobar to uranium 238.
b. If this nucleus lost the equivalent of a helium 4 nucleus, what element would uranium 238 become?
Solution
i. isotope -> have same number of protons but different mass number. (different number of nuetrons)
U238 : have 92 protons and 146 nuetrons.
Isotopes of U238 = 232U , 2333U, 234U, 235U, 236U
all have 92 protons but different nutrons,
II.
Isotone = elements which have same number of nuetrons but different proton numbers.
U238 : have 92 protons and 146 nuetrons.
Isotone of U238 = 236 Th (Thorium)
no. of protons = 90 , no of neutrons = 146
III. Isobars= have same number of nucleons (protons + nuetrons) OR mass number but different number of electrons.
Isotone of U238 = 238 Th
b. helium have 2 protn and 2 neutrons.
so now 238U will have 90 protons and 144 nuetrons.
so it will become thorium.
having mass number of 234.
