Chegg Untitled document Goog X C https docsgoogleco EE Apps
Solution
Let X = years of education.
Y = number of fue tickets.
We have to find sample correlation coefficient (r) between X and Y.
r = SSxy / sqrt(SSx*SSy)
where SSxy = XY - [ (X*Y)/ n ]
SSx = X2 - [(X)2 / n ]
SSy = Y2 - [(Y)2 / n ]
where n is the number of data pairs.
For this we have to make a table of summation as,
SSxy = 685 - [ (96*77) / 9 ] = -136.333
SSx = 1152 - (96^2/9) = 128
SSy = 905 - (77^2/9) = 246.2222
r = -136.333 / sqrt(128*246.2222)
r = -0.76795 = -0.77
option a) is correct.
We are given that alpha = 0.05
critical value = 0.666
Test of the hypothesis is,
H0 : = 0 Vs H1 : 0
we already calculated r = -0.77
Now we have to compare r with critical value.
| r | > critical value
reject H0 at 0.05 significance level.
Conclusion : Population correlaion cofficient differ than 0.
Option a) is correct.
| X | Y | XY | X^2 | Y^2 | 
| 6 | 18 | 108 | 36 | 324 | 
| 7 | 10 | 70 | 49 | 100 | 
| 8 | 14 | 112 | 64 | 196 | 
| 9 | 6 | 54 | 81 | 36 | 
| 10 | 12 | 120 | 100 | 144 | 
| 11 | 2 | 22 | 121 | 4 | 
| 12 | 8 | 96 | 144 | 64 | 
| 14 | 6 | 84 | 196 | 36 | 
| 19 | 1 | 19 | 361 | 1 | 
| 96 | 77 | 685 | 1152 | 905 | 


