If a projectile is fired with velocity v0 at an angle theta

If a projectile is fired with velocity v_0 at an angle theta, then its range, the horizontal distance it travels (in feet), is modeled by the function r(theta) = V_o^2 sin 2theta/32 If v_0 = 2700 ft/s, what angle (in degrees) should be chosen for the projectile to hit a target on the ground 7000 ft away? (Enter your answers as a comma-separated list. Round your answers to three decimal places.)

Solution

sin(2theta) = (7000)32/(2700)^2 = 112/3645

2theta = 1.761,181.761
theta = .8805,90.8805