Thermodynamics Question 2 Follow Link Below for question ple

Thermodynamics

Question 2: Follow Link Below for question please.

http://imgur.com/vNZ3bei

Refrigerant-134a at 320 kPa and 22degreeC flows through a refrigeration line. Determine its specific volume.

Solution

From Superheated refrigerant R-134a ,A-13 Table for P=320 Kpa ,we cannot directly obtain the specific volume at 22^oC ,so we have take 20^oCand 30^oC values and interpolate it to at T= 22^oC.So

at T₁=20^oC =>v₁=0.06925 m³/kg

at T₂=30^oC=>v₂=0.07231 m³/Kg

So By interpolartion for T=22^oC

v = v₁+[(T-T₁)/(T₂-T₁)](v₂-v₁)

v= 0.06925+[(22-20)/(30-20)]*(0.07231-0.06925)

v=0.069862 m³/kg