12 The customer service department of a local gas utility wa
12. The customer service department of a local gas utility wants to estimate the average length of time between the entry of the service request and the connection of service. A random sample of 10 houses is selected from the records available during the past year. The results recorded in number of days are as follows.
114 78 96 137 78 103 117 126 86 99
Assuming the distribution of time as normal, construct a 95% confidence interval estimate of the average length of time (m)
I really need help for this question!!
Solution
sample mean=103.4
sample standard deviation=20.01222
The degree of freedom =n-1=10-1=9
Given a=1-0.95=0.05, t(0.025, df=9)=2.26 (from student t table)
So the lower bound is
xbar -t*s/vn=103.4-2.26*20.01222/sqrt(10) =89.09777
So the upper bound is
xbar +t*s/vn=103.4+2.26*20.01222/sqrt(10) =117.7022
