For the data below plot using graph paper or software a Line

For the data below, plot (using graph paper or software) a Lineweaver-Burke plot of the data in order to determine the KM and Vmax of the enzyme in the presence and absence of inhibitor. Is this inhibitor: competitive, noncompetitive, uncompetitive, or irreversible?
[s] mM.      v° w/o inhibitor.   v°w/inhibitor
1.                2.5.                         1.17
2.                4.0.                          2.10
5.                6.3.                          4.00
10.              7.6.                          5.7
20               9.0.                          7.2
                    micoM/s.               microM/s

Solution

s   v-i   v+i       1/s   1/v-i   1/v+i
1   2.5   1.17       1   0.4   0.854700855
2   4   2.1       0.5   0.25   0.476190476
5   6.3   4       0.2   0.158730159   0.25
10   7.6   5.7       0.1   0.131578947   0.175438596
20   9   7.2       0.05   0.111111111   0.138888889

vmax(-i)   10.13171226   km(-i)   3.056737589

vmax(+i)   10   km(+i)   7.541

where vmax(-i),km(-i)=without inhibitor

vmax(i),km(+i)-with inhibitor

as km with inhibitor is greater then km without inhibitor it is competitive inhibitor