Sin B1cosB 1 cos Bsin B SolutionsinB1cosB multiplyand divi

Sin B/1-cosB = 1 + cos B/sin B

sinB/(1-cosB)

multiplyand divide by (1+cosB)

=sinB(1+cosB)/[(1-cosB)(1+cosB)]

=sinB(1+cosB)/[(1-cos²B)]

we know sin²x +cos²x=1 =>sin²x =1-cos²x

=sinB(1+cosB)/(sin²B)

=(1+cosB)/(sinB)

Sin B/1-cosB = 1 + cos B/sin B SolutionsinB/(1-cosB) multiplyand divide by (1+cosB) =sinB(1+cosB)/[(1-cosB)(1+cosB)] =sinB(1+cosB)/[(1-cos2B)] we know sin2x +c

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