Chapter 2 Problem 2062 Replace the 38kN force by an equivale

Chapter 2, Problem 2/062 Replace the 3.8-kN force by an equivalent force-couple system at (a) point O and (b) point B. Give your answers in vector format y, m 40 5.9 m B (5.2,2.4) 3.8 kN l o x, m

Solution

The horizontal component of force=-3.8cos40=-2.91 kN

The vertical component of force=-3.8sin40=-2.44 kN

a)Force in vector form =-2.91i -2.44j kN

Moment of force about O=2.44*5.9=14.4 kNm(anticlockwise)

Moment of force about O in vector form= 14.4 k kNm

b) force in vector form=-2.91 i -2.44 j kN

Moment of force about point B=2.91*(5.9-2.4)+2.44*5.2 =22.87 kNm

Moment about B in vector form=22.87 k kNm