Solve the triangle a1 b10 C40 degrees Do not round until the

Solve the triangle:

a=1, b=10, C=40 degrees

Do not round until the final answer. Then round to the nearest tenth as needed.

c=?

A= ? Degrees

B= ? Degrees

Using cosine rule:

c^2 = a^2 +b^2 -2abcosC

= 1^2 + 10^2 -2*1*10cos40

=85.68

c = 9.26

Using sine rule now:

c/sinC = a/sinA

sinA = a*sinC/c = 1*sin40/9.26 = 0.024

A = 1.41 deg , (180 -1.41 = 178.5 is not possible solution)

B = 180 - ( 40 + 1.41) = 138.59 deg

After rounding off: c = 9.3

A = 1.4 deg

B = 138.6 deg