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P Take a Test Austin Vest- Google Chrome https: Student/Player eyes Test: Math Placement Test Part 2 Precalculus This Question: 1 pt Solve the right triangle shown in the figure. a. What are the lengths of the sides? a (Round to the nearest hundredth as needed.) bs (Round to the nearest hundredth as needed.) b. What are the angles? B- o (Round to the nearest tenth as needed.) Enter your answer in each of the answer boxes. HE Search the web and Windows 10 of 20 (0 complete) Austin Vest 1/15/16 1:53 PM Time Remaining: 00:58:44 Submit Test This Test: 20 pts possible 1:53 PM 1/15/2016

Solution

A=55.5^o,c=52

from the diagram

triangle is a right angled triangle with right angle at C

C=90^o

A+B+C=180^o

B=180^o-A-C

B=180^o-55.5^o-90^o

B=34.5^o

LAW SINES :

a/sinA =b/sinB =c/sinC

a/sinA =c/sinC

a/sin55.5^o =52/sin90^o

a/sin55.5^o =52/1

a=42.85

b/sinB =c/sinC

b/sin34.5^o =52/sin90^o

b =52sin34.5^o

b=29.45