Homework SourseIf log x5 y3 25 and logxy3 then find logy This is what I go
If log x^5 y^3 = 25 and log(x/y)=3, then find log(y)
This is what I got so far: log x^5 + log y^3=25, 5logx +3logy=25
- 5logx +5logy= -15
For log(x/y)=3, (logx-logy)=(3)(-5)
I\'m not sure if I did this right. Could someone help me solve the rest of this problem. Thanks!
This is what I got so far: log x^5 + log y^3=25, 5logx +3logy=25
- 5logx +5logy= -15
For log(x/y)=3, (logx-logy)=(3)(-5)
I\'m not sure if I did this right. Could someone help me solve the rest of this problem. Thanks!
Solution
log x^5 y^3 = 25
log(x/y)=3
So,we have,
5 log x + 3 log y = 25
log x - log y = 3
So, 5 log x + 5 log y = 15
So,
log y = -10/2 = -5
