Answer the following seven questions a through g based upon
Solution
Answers
a) Q: Glutamine I: Isoleucine K: Lysine
b) Q: gln I: Ile (ILE) K: Lys
c) +1 (i.e) one positive charge
Explanation: The overall charge at pH 7 is decided by the charge on the side chains of the aminoacids. The peptide doesn\'t add to the net charge as positive charge at the amino end gets balanced by one negative charge at the carboxy end. So in the tripeptide, Q I K, one addtional positive charge will be contributed by the additional amino group present in the side chain of K (Lysine)
d) Q: Uncharged, Polar ( if you can select only one select polar) I : Hydrophobic, uncharged ( if you can select only one select hydrophobic) K: positively charged
e) Answer: +2 (i.e 2 positive charge, as a whole number you can enter \'2\')
Explanation: At very low pH like 1.0 in this question, there is an abundance of H+ ions in solution so the -COOH groups do not dissociate to -COO- whereas the positive charge on -NH2 group remains intact. Since, tripeptide Q-I-K will have two -NH2 groups, it has a net positve charge (+2)
f) Answer: - 1 (i.e. 1 minus charge or minus 1)
Explanation : At very high pH like pH11.5 in this question, there are more -OH- ions in the solution and thus the COOH groups release the H+ ions and become negatively charged. The NH2 groups do not acquire H+ ions and thus say neutral. So in the tripeptide Q-I-K, there is net of one negative charge !
g) Answer : Hydrogen bonds
