y 6x y 36x2Solution OOPS Sorry there was mistake in second

y = 6-x

y= 36-x^2

Solution

OOPS Sorry ; there was mistake in second term of area (i.e. area2) should be Integral {(30-x^2+x)dx} instead of Integral {(30-x^2-x)dx} in previous submission. Now it is Corrected; Check this This is OK Area1 = Integral {((6-x)-(36-x^2))dx} = Integral {(x^2-x-30)dx} ; limits from -6 to-5 =5.833 Area2 = Integral {((36-x^2)-(6-x))dx} = Integral {(30-x^2+x)dx} ; limits from -5 to 6 = 221.833 Area3 = Integral {((6-x)-(36-x^2))dx} = Integral {(x^2-x-30)dx} ; limits from 6 to 7 = 5.833 Total shaded area = Area1 + Area2 + Area3 =5.833 + 221.833 +5.833 = 233.5 if u dont get this message me