Many polls have asked people whether they are trying to lose
Solution
a.
 Sample 1 : X1 =110, n1 =500, P1= X1/n1=0.22
 Sample 2 : X2 =120, n2 =500, P2= X2/n2=0.24
 b.
 Null Hypothesis, There Is No Significance between them Ho: p1 = p2
 Alternate Hypothesis, There Is Significance between them H1: p1 != p2
 Test Statistic
 Finding a P^ value For Proportion P^=(X1 + X2 ) / (n1+n2)
 P^=0.23
 Q^ Value For Proportion= 1-P^=0.77
 we use Test Statistic (Z) = (P1-P2)/(P^Q^(1/n1+1/n2))
 Zo =(0.22-0.24)/Sqrt((0.23*0.77(1/500+1/500))
 Zo =-0.751
 | Zo | =0.751
 Critical Value
 The Value of |Z | at LOS 0.05% is 1.96
 We got |Zo| =0.751 & | Z  | =1.96
 Make Decision
 Hence Value of |Zo | < | Z  | and Here we Do not Reject Ho
 P-Value: Two Tailed ( double the one tail ) -Ha : ( P != -0.7514 ) = 0.4524
 Hence Value of P0.05 < 0.4524,Here We Do not Reject Ho
c.
 Sample 1 : X1 =1100, n1 =5000, P1= X1/n1=0.22
 Sample 2 : X2 =1200, n2 =5000, P2= X2/n2=0.24
 Finding a P^ value For Proportion P^=(X1 + X2 ) / (n1+n2)
 P^=0.23
 Q^ Value For Proportion= 1-P^=0.77
 we use Test Statistic (Z) = (P1-P2)/(P^Q^(1/n1+1/n2))
 Zo =(0.22-0.24)/Sqrt((0.23*0.77(1/5000+1/5000))
 Zo =-2.376
 | Zo | =2.376
 P-Value: Two Tailed ( double the one tail ) -Ha : ( P != -2.3762 ) = 0.0175
 Hence Value of P0.05 > 0.0175,Here we Reject Ho
d.
 With size 500, we Failed to Reject Ho
 With size 5000, we Reject Ho

