Many polls have asked people whether they are trying to lose
Solution
a.
Sample 1 : X1 =110, n1 =500, P1= X1/n1=0.22
Sample 2 : X2 =120, n2 =500, P2= X2/n2=0.24
b.
Null Hypothesis, There Is No Significance between them Ho: p1 = p2
Alternate Hypothesis, There Is Significance between them H1: p1 != p2
Test Statistic
Finding a P^ value For Proportion P^=(X1 + X2 ) / (n1+n2)
P^=0.23
Q^ Value For Proportion= 1-P^=0.77
we use Test Statistic (Z) = (P1-P2)/(P^Q^(1/n1+1/n2))
Zo =(0.22-0.24)/Sqrt((0.23*0.77(1/500+1/500))
Zo =-0.751
| Zo | =0.751
Critical Value
The Value of |Z | at LOS 0.05% is 1.96
We got |Zo| =0.751 & | Z | =1.96
Make Decision
Hence Value of |Zo | < | Z | and Here we Do not Reject Ho
P-Value: Two Tailed ( double the one tail ) -Ha : ( P != -0.7514 ) = 0.4524
Hence Value of P0.05 < 0.4524,Here We Do not Reject Ho
c.
Sample 1 : X1 =1100, n1 =5000, P1= X1/n1=0.22
Sample 2 : X2 =1200, n2 =5000, P2= X2/n2=0.24
Finding a P^ value For Proportion P^=(X1 + X2 ) / (n1+n2)
P^=0.23
Q^ Value For Proportion= 1-P^=0.77
we use Test Statistic (Z) = (P1-P2)/(P^Q^(1/n1+1/n2))
Zo =(0.22-0.24)/Sqrt((0.23*0.77(1/5000+1/5000))
Zo =-2.376
| Zo | =2.376
P-Value: Two Tailed ( double the one tail ) -Ha : ( P != -2.3762 ) = 0.0175
Hence Value of P0.05 > 0.0175,Here we Reject Ho
d.
With size 500, we Failed to Reject Ho
With size 5000, we Reject Ho
