Mens Heights are normally distributed with a mean of 6900 in

Men\'s Heights are normally distributed with a mean of 69.00 inches and a standard deviation of 2.8 inches. Find the probabilities for the given values. Round to four decimal places. Probability that a randomly selected male is between 61 and 67 inches

Solution

P(61<X<67) = P[(61-69)/2.8 < Z < (67-69)/2.8]

= P (-2.86< Z < -0.71)

= P(Z <-0.71) - P(Z<-2.86)

= 0.2389 - 0.0021

= 0.2386