It has been claimed that at UCLA at least 40 of the students
Solution
H0: P=P0
H1:P>P0
P0=0.4
P=90/250
Z=P-P0/sqrt(P0Q0/n)
z=-1.29
p is 0.9016, hence we accept H0.

H0: P=P0
H1:P>P0
P0=0.4
P=90/250
Z=P-P0/sqrt(P0Q0/n)
z=-1.29
p is 0.9016, hence we accept H0.
