8 10 pts A 40cmtall object is placed S00 cm from a diverging

8. (10 pts) A 4.0-cm-tall object is placed S0.0 cm from a diverging lens having a focal length of from a diverging lens having a focal lesn of magnitude 25.0 cm. What is the nature and location of the image? A) A virtual image, 20 cm tall, 10 cm other side of the object B) A virtual image, 4.0 cm tall, 20 cm other side of the object C) A real image, 1.3 cm tall, 16.7 cm same side as the abject D) A real image, 4.0cm tall, 20 cm other side of the object E) A virtual image, 1.3 cm tall, 16.7 same side as the object

Solution

1/do + 1/di = 1/f

1/di = 1/f - 1/do = [1/-25] - [1/50]

di = -16.67 cm

image is virtual

m = -di / do = 16.67 / 50

= 0.333 [ image is upright and 1.33 cm tall]

E) A virtual image, 1.3 cm tall, 16.7 cm same side as the object