Find the polynomial fx of degree 7 such that both 2 and 2 ar
Find the polynomial f(x) of degree 7 such that both 2 and -2 are zeros of multiply 2 ,0 is a zero of multiplicity 3 ,and f(-1) = -36
Solution
polynomial f(x) of degree 7 such that both 2 and -2 are zeros of multiply 2 ,0 is a zero of multiplicity 3 ,and f(-1) = -36
-----> 2 and -2 are zeros of multiply 2 : ( x-2)^2(x+2)^2
------> 0 is a zero of multiplicity 3 : x^3( x-2)^2(x+2)^2
Let f(x) = kx^3( x-2)^2(x+2)^2
Given : f(-1) = -36
So, -36 = k(-1)(-3)^2(1)^2
-36 = -k*9
k = 4
So, f(x) = 4x^3( x-2)^2(x+2)^2
